[oz / tsp (imp)] to [lb t / cu ft]

Convert density from ounce (US food nutrition labelling) per teaspoon (imperial) to pound (troy) per cubic foot.
Conversion number is 0.023254319047093, this means that ^oz⁄_{tsp (imp)} is smaller unit compared to ^{lb t}⁄_{cu ft.}

Enter the density in ^{ounce (US food nutrition labelling)}⁄_{teaspoon (imperial)}

	oz
	tsp (imp)

0.023254319047093	lb t
	cu ft

Result is in ^{pound (troy)}⁄_{cubic foot} .
Calculation process:

oz / tsp (imp)

0.028 [kg/oz] / 5760.0000000000 [kg/lb t]

0.028316846592 [m³/cu ft] / 5.91938802083333E-06 [m³/tsp (imp)]

= 0.023254319047093

lb t / cu ft

Bulk conversion [oz / tsp (imp)] => [lb t / cu ft]

[oz/tsp (imp)][lb t/cu ft]

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You can enter your own numbers (one per line) or just generate some numbers and convert them. The results you can copy-paste to Excel for example.

More about base units:

• 1 ounce (US food nutrition labelling) [oz] ≡ 28 g = 0.028 kg, definition: The ounce (abbreviated oz) is a unit of mass used in most British derived customary systems of measurement.. US Code of Federal Regulations, Title 21, Section 101.9, Paragraph (b)(5)(viii), retrieved August 29, 2009 (link moved, 2017-04-04)
• 1 teaspoon (imperial) [tsp (imp)] ≡ 1⁄24 gi (imp) = 5.91938802083333E-06 m³, definition: Imperial teaspoon is volume unit (widely used in cooking recipes) equivalent with 1/24 of imperial gill = 5.91938802083×10⁻⁶ m³. In fraction: 1 tsp (imp) ≡ 1.420653125/240000 m³. conversion.org/volume/teaspoon-imperial/
• 1 pound (troy) [lb t] ≡ 5760 grains = 5760.0000000000 kg, definition: 64.79891 g x 5760 = 0.3732417216 kg. National Institute of Standards and Technology (October 2011). Butcher, Tina; Cook, Steve; Crown, Linda et al. eds. Appendix C – General Tables of Units of Measurement (PDF) p. C-6
• 1 cubic foot [cu ft] ≡ 1 ft × 1 ft × 1 ft = 0.028316846592 m³, definition: ≡ 0.3048³ = 0.028316846592 m³. See also: International foot

[kg/m³] kg-m3.com All about density